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Tanzania [10]
3 years ago
7

The simplified form of an expression is 1/258 t^28. Which expression was simplified

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
7 0
<span>1/258 *(t^28)
= t^28 / 4^4
= t^28 4^-4
= (t^-7 * 4)^-4
= (4t^-7)^-4

answer is D. last option</span>
DochEvi [55]3 years ago
5 0

Answer:

d (4t^-7)^-4

Step-by-step explanation:

give me brainliest also dont look at my name

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Answer:

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Your equation is:

 

0.5x + 0.05(500) = 0.2(500+x)

 

Solve for x to find the grams of 50% silver used

 

Step-by-step explanation:

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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
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Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

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16x^2-64x+5=0

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\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

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\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

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