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3 years ago

Heather collects shells. The picture shows the 18 shells that she found on her family beach vacation. She wants to use all of

1 answer:

6 0

Answer:
D) 9 postcards with 2 shells each.

Explanation:
9 x 2 = 18
Therefore, 9 postcards with 2 shells each is the correct answer.

Please give brainliest.

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What is the algebraic expression for the quotient of j and 8

Dmitrij [34]

The algebraic expression for the quotient of j and 8 is j/8. Fractions are quotients.

7 0

3 years ago

Find the Range and Domain of the Binary relations

sukhopar [10]

Answer:

A = {3,5,6}

B = {1,3}

A x B = {(3,1),(3,3),(5,1),(5,3),(6,1),(6,3)}

Domain of A x B = (The x figures in ascending order)

=> {3,5,6} (Figures repeating more than once must be written only 1 time)

Range of A x B = (The y figures in ascending order)

=> {1,3}

B x A = {(1,3),(3,3),(1,5),(3,5),(1,6),(3,6)}

Domain of B x A = {1,3}

Range of A x B = {3,5,6}

8 0

3 years ago

Part B Can image 2 be the reflected figure? Explain your answer.

Anastaziya [24]

Answer:

Yes it can be be the reflected figure

4 0

3 years ago

A lighthouse is located on a small island 5 km away from the nearest point P on a straight shoreline and its light makes seven r

Vaselesa [24]

Answer:

Light is moving at the speed = 77.78 km/min

Step-by-step explanation:

Given:

Distance between island and point P = 5 km

Moving along the the shoreline when it is 1 km from P.

So, x = 1

From the above statement light makes seven revolutions per minute.

Therefore,

$\frac{d\theta}{dt}=\frac{7\times 2\pi\ rad}{1\ min} = 14\pi\ rad/min$

Solution:

From the given figure.

$tan\theta=\frac{x}{5}$

Substitute x = 1

$tan\theta=\frac{1}{5}$ -------------------(1)

Now, first we differentiate both side with respect to t.

$\frac{d(tan\theta)}{dt} = \frac{d}{dt}.(\frac{x}{3})$

Using chain rule.

$\frac{d(tan\theta)}{dt}.\frac{d\theta}{dt} = (\frac{1}{5})\frac{dx}{dt}$

$sec^{2} \theta.\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

$(1+tan^{2} \theta).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

Substitute $tan\theta=\frac{1}{5}$ from equation 1.

$(1+(\frac{1}{3})^{2} ).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

$(1+\frac{1}{9}).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}$

Substitute $\frac{d\theta}{dt}=14\pi$

$\frac{10}{9}.14\pi = \frac{1}{5}.\frac{dx}{dt}$

Applying cross multiplication rule.

$\frac{dx}{dt}= \frac{700\pi }{9}$

$\frac{dx}{dt}= 77.78\pi$

Therefore, light is moving along the shore at the speed of 77.78 km/min

6 0

3 years ago

¿En cuál de los siguientes intervalos están solo los números reales que pertenecen a ] –3 , 5 ] y no pertenecen a [ –1 , 7 [?

vitfil [10]

Complete question:

¿En cuál de los siguientes intervalos están solo los números reales que pertenecen a ]- 3,5 ] y no pertenecen a [ –1 , 7 [ ?

A) ]-3, -1[

B) ]- 3, -1 ]

C) [-1,5]

D) ]- 3,7[

E) [5,7[

Answer:

A) ]-3, -1[

Step-by-step explanation:

El intervalo ]- 3,5 ] incluye a todos los números que se encuentran entre -3 y 5. Es decir,

...-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6...

El intervalo [–1 , 7[ excluye a los números que se encuentran entre -1 y 7, pero incluye a todos los números que sean menores a -1 y a todos los mayores a 7. Es decir,

...-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 13...

Para responder el problema, debemos encontrar aquellos números reales que se incluyan dentro de ambos intervalos. Esto es,

]- 3,5 ] ...-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10...

]- ∞ , -1[ ∪ [7,∞[...-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10...

Es decir que el intervalo ]-3, -1[, corresponde a la intersección entre ambos conjuntos.

8 0

2 years ago