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swat32
3 years ago
8

Using the slope and the y-intercept, graph the line represented by the following equation. Then select the correct graph. 3y = 2

x - 6

Mathematics
2 answers:
Over [174]3 years ago
5 0
First, let's write the given equation in slope-intercept form: y = mx + b

In slope-intercept form, the slope of the line is m, and the y-intercept is b. The slope is a measure of how steep the graph is at any point and is found by doing rise over run. This means the change in y values divided by the change in x values. Next, y-intercept is just where the graph crosses the y axis.

All we need to do to get the equation in slope-intercept form is to divide each term by 3. This will isolate the y.

y= \frac{2}{3}x-2

As you can see, the slope of the line is 2/3, and the y-intercept is -2.

To graph the line, plot a point at (0,-2). This is the point where the graph crosses the y axis. Then from that point, count up two and right 3. Plot a point here as well. Lastly, connect the two points with a straight line.

See attached picture for the graph.

AlexFokin [52]3 years ago
4 0
3y = 2x - 6÷3 both sides y=2/3x-2
equation:slope: 2/3 y intercept: -2
graph 1: slope: 2y intercept: 4
graph 2: slope: 2/3y intercept: -2
graph 3:slope: 1y intercept: -3
graph 4:slope: 0y intercept: -2
equation : graph 2
 
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Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

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3 years ago
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