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3 years ago

Cuales son los divisores comunes de 3,9y12

Mathematics

1 answer:

noname [10]3 years ago

8 0

Los divisores comunes de 3, 9 y 12 son:
1, y 3
explication: el tres solo puede ser dividido por estos numeros

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YALL PLEASE HELP, need to turn this in ASAP

Colt1911 [192]

Answer:

I believe the answer is 1,800 :)

Step-by-step explanation:

1,500x0.20=300+1,500=1,800

Hope this helped!

7 0

3 years ago

Plot the point in a complex plane -3+4i

Marianna [84]

The image below shows this equation on a complex plane.

3 0

3 years ago

Read 2 more answers

HURRY ILL GIVE U BRAINLIEST!!! Find the area of each figure. Which do these belong in?

nordsb [41]

Answer:

Area of rectangle PQRS is 14 square units.

Area of triangles UVW and EFG and square ABCD are 16 square units each.

Step-by-step explanation:

Let us find the area of each of the figures shown in the graph.

Area of rectangle PQRS is given as the product of PQ and QS.

From the graph,

Length of PQ = 7 units

Length of QS = 2 units

Now, area of rectangle PQRS = $PQ\times QS=7\times 2=14$ square units.

Now, area of square ABCD is given as the square of any of its side.

From the graph, AB = 4 units.

So, area of ABCD = $AB^{2}=4^2=16$ square units.

Area of triangle UVW is given as the half of the product of its base VW and height UW.

From the graph, UW = 4 units, VW = 8 units

Therefore, area of triangle UVW = $\frac{1}{2}\times UW\times VW=\frac{1}{2}\times 4\times 8=16$ square units.

For triangle EFG, EF = 4 units and FG = 8 units.

Area = $\frac{1}{2}\times EF\times FG=\frac{1}{2}\times 4\times 8=16$ square units.

Area of rectangle PQRS is 14 square units. The remaining figures have areas each equal to 16 square units.

4 0

3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

2 years ago

Carla has already written 10 pages of a novel. she plans to write 15 additional pages per month until she is finished. write and

grin007 [14]

Linear Equation: 15m+10=w
15 pages written for every month for 5 months plus the 10 pages she has already written is equal to the total number of pages written in 5 months.
m= number months written. In this case, it is 5 months.
w= number of pages written in 5 months
15(5)+10=w
75+10=w
85 pages written=w
Carla will have written 85 pages in 5 months.

4 0

2 years ago