Answer:
(√9)^2x-1/2 = 1/81
3^2x-1/2 = 1/(3)⁴. (as √9 = 3)
3^2x-1/2 = 3^-⁴. (as 1/a^m = a^-m)
as base are equal exponents are equal
so 3 gets cancelled out
2x-1/2 = -4
(4x-1)/2 = -4
4x-1 = -8
x = -7/4
hope this helps
Step-by-step explanation:
Answer:
5 per noun, 8 per verb
Step-by-step explanation:
start by defining what each variable is
v = n+3
v = 2n-2
substitute v for one of the equations above
n+3 = 2n-2
subtract n from both sides
3 = n-2
add 2 to each side
5 = n
so there are 5 flashcards per noun
substitute 5 in for n in both equations
v = 5+3
and
v = 2(5)-2
solve both equations
v = 8 and v = 8
so there are 8 flashcards per verb
Answer:
4095
Step-by-step explanation:
3(4⁰) + 3(4¹) + 3(4²) + 3(4³) + 3(4⁴) + 3(4⁵)
3(4⁰ + 4¹ + 4² + 4³ + 4⁴ + 4⁵)
3(1 + 4 + 16 + 64 + 256 + 1024)
3 * 1365 = 4095
There is one restriction: The number whose square root is needed can not be negative
