Answer:
24
Step-by-step explanation:
IDK
The solutions of the equations of the situation can be:
z = 1 , y = 5, x = 4
z= 2 , y = 3, x = 5
z=3 , y = 1, x = 6
z = 0 , y = 7, x =3
The question can be expressed as a equation
6 x + 8 y + 10 z = 84
also, x + y + z = 10
⇒ x = 10- y - z
Putting it in first equation,
6(10 - y - z ) +8y + 10z = 84
⇒ 60 +2y + 4z = 84
⇒2(y + 2z ) = 14
⇒ y + 2z = 7
Now putting
z = 1 , we get y = 5,
z= 2 , y = 3
z=3 , y = 1
z = 0 , y = 7
So, only 4 possible solutions.
Therefore, there can only be 4 possible solutions for the equations.
"Learn more about linear equation here-
brainly.com/question/28442870 "
#SPJ9
Answer:
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
1. Plug in the values.
q=10
p=-6
10÷2-(10)(-6)÷6
2. Use PEMDAS.
10÷2+60÷6
5+10
15
Using the properties of percentages we can calculate that there are 200 kids in the archery camp that summer.
Long before the decimal numeral system, Ancient Rome routinely computed in fractions as multiples of 1/100.
A percentage is a dimensionless (pure) number; it has no unit of measurement.
The % value is determined by multiplying the numerical value of the ratio by 100. To calculate 50 apples as a percentage of 1250 apples, first compute 50/1250 = 0.04, then multiply by 100 to get 4%.
Let the total number of kids in the camp be x.
The number of kids who took archery = 25%
But 50 students took archery.
hence 25% of x = 50
Solving we infer:
x = 200
Therefore there are 200 kids in the camp.
To learn more about percentages visit:
brainly.com/question/15840409
#SPJ1
