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2 years ago

15

Mary wants to find an expression she can use to determine how far she has traveled. She knows that her distance is represented b

y (-24x^3 - 70x^2 - 59x - 15) And that her time is represented by (2x + 1).
Which expression, in simplest terms, represent her rate?

1 answer:

Ivahew [28]2 years ago

3 0

Answer: this one is confusing

Step-by-step explanation:

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The measure of the angle is half the measure of the opposite arc.
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What is the coefficient in the expression 5x^2 +3 ?<br> A. 5<br> B. X<br> C. 3<br> D. 2

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Answer:

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Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

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15w
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Answer:

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Step-by-step explanation:

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