Given:
Point D is incenter of ΔBCA.
m∠FDG = 136°
To find:
The measure of ∠FHG
Solution:
<em>Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.</em>
Divided by 2 on both sides.
Substitute m∠FDG = 136°
The measure of ∠FHG is 68°.
Answer:
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Step-by-step explanation:
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Answer:
ok, this is what i mean. if you dont unerstand then stop it yes ok,ay hanks you
Step-by-step explanation:
The given above is are triangles, as per the proof the line segments on top and bottom part are parallel. Also, it is given that two pairs of the angles of the triangles are congruent.
The triangles also share one common side, CA. Since, this side is between the angles the postulate that will prove the congruence of the triangles is ASA.
The answer to this item is the third choice.
Answer:
18750
Step-by-step explanation:
