(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Answer:
5(x+2)=6x+3x−14
Step 1: Simplify both sides of the equation.
5(x+2)=6x+3x−14
(5)(x)+(5)(2)=6x+3x+−14(Distribute)
5x+10=6x+3x+−14
5x+10=(6x+3x)+(−14)(Combine Like Terms)
5x+10=9x+−14
5x+10=9x−14
Step 2: Subtract 9x from both sides.
5x+10−9x=9x−14−9x
−4x+10=−14
Step 3: Subtract 10 from both sides.
−4x+10−10=−14−10
−4x=−24
Step 4: Divide both sides by -4.
−4x
−4
=
−24
−4
x=6
Answer:
x=6
x,y = 9,5 is the answer no it not
Given:
Gracie is sharing 75 marshminnows among 4 of her friends.
Each of her friends gets the same number of marshminnows, and she gives them as many marshminnows as possible.
To find:
The remaining number of marshminnows she has.
Solution:
We have,
Total number of marshminnows = 75
Number of friends = 4
Divide 75 by 4.
Here, quotient is 18 and remainder is 3. It means, each friend can be get maximum 18 marshminnows and the number of remaining marshminnows is 3.
Therefore, the correct option is B.
This is the answer. Let me know if i'm correct.
