Answer:
x^2+5x-14
Step-by-step explanation:
you multiply both equations so that you get:
x^2-2x+7x-14
and then you simplify it to:
x^2+5x-14
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First multiply them out to improper fractions 1 3/5 changes into 8/5 and 1 2/5 changes into 7/5 multiply them out and you should get 2 6/25.
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
79
Step-by-step explanation:
So we have the function:
To find g(9), substitute 9 for t. Thus:
Square:
Subtract:
So, our answer is 79.
And we're done!
