*I think you meant scientific notation.*
23 in scientific notation would be 2.3 x 10^1.
Volume of a Cylinder = πr²h
V = π * (11)² * 15
v = π * 121 * 15
v = 1815π units³
In short, Your Answer would be Option C
Hope this helps!
The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
</span>
The values of x are 2 and -1.
Solving the equation created by substitution listed in the question:
-2x+14=x²-3x+12
Add 2x to both sides:
-2x+14+2x=x²-3x+12+2x
14=x²-1x+12
Subtract 14 from both sides:
14-14=x²-1x+12-14
0=x²-1x-2
Factoring this, we want factors of -2 that sum to -1; -2(1) = -2 and -2+1=-1:
0=(x-2)(x+1)
Using the zero product property, we know that either x-2=0 or x+1=0:
x-2=0
x-2+2=0+2
x=2
x+1=0
x+1-1=0-1
x=-1
Their are 16 logs the stove burn in 8hours
