the assumption here being that both lines JH and FH are tangent lines to the circle, if that's the case the external angle of 34° is the angle made by the equal tangents, meaning the triangle is an isosceles with twin sides.
In an isosceles triangle the twin sides make also twin angles, so the angles at J and F are twins, and they'd be 180° - 34° = 146° total, since they're twins, each one takes half, or 73°.
Answer:
y=4x-5.
Step-by-step explanation:
slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;
1) to find value of k:
if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;
2) to find the value of 'b':
if to substitute the given coordinates into the equation of the given line, then:
15=4*5+b, b= -5.
3) finally, y=4x-5
Answer:
20°
Step-by-step explanation:
One way of doing this is to find the constant of proportionality, k:
8k + 6k + 4k = 90° Then 18k = 90°, and k turns out to be 90/18, or 5.
Then the angles are 8(5), 6(5) and 4(5). The smallest of these angles is thus 20°
Answer:
Equation of the tangent to the curve
y = 240x - 215994
Equation of the normal
y = (-1/240)x + 9.75 = - 0.00417x + 9.75
Step-by-step explanation:
y = (6 + 4x)² = 36 + 48x + 16x² = 16x² + 48x + 36
dy/dx = 32x + 48
At the point (6,900),
dy/dx = 32(6) + 48 = 240
Equation of the tangent at point (a,b) is
(y - b) = m(x - a)
a = 6, b = 900, m = 240
y - 6 = 240(x - 900)
In the y = mx + b form,
y - 6 = 240x - 216000
y = 240x - 215994
The slope of the normal line = -(1/slope of the tangent line) (since they're both perpenducular to each other)
Slope of the normal line = -1/240
Equation of normal
y - 6 = (-1/240)(x - 900)
y - 6 = (-x/240) + 3.75
y = (-1/240)x + 9.75
y = - 0.00417x + 9.75
Answer: 31.5 in.
Answer:
the answer is 13 cm
Step-by-step explanation:
