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IgorLugansk [536]
4 years ago
14

How to solve this problem?

Mathematics
1 answer:
klio [65]4 years ago
8 0
Assuming that says a² + B² and not a² ÷ B², your answer would be 5.

To answer this question you need to find the value of a and B, which you can do by finding the roots of x² - 3x + 2 = 0. You can do this by factoring the equation to get (x - 2)(x - 1) = 0, and so x = 2 or x = 1.

Then, we just need to square 2 and 1, and add them, giving us 4 + 1 = 5.

I hope this helps!
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Five more than 6 times a number is 77.what is the number
Nadusha1986 [10]

Answer:

12

The drawing will help

4 0
3 years ago
Read 2 more answers
A line passes through the point (8,-5) and has a slope of 3/2
Tresset [83]

Answer:

y=3/2x-17

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=3/2(x-8)

y+5=3/2(x-8)

y=3/2x-24/2-5

y=3/2x-12-5

y=3/2x-17

6 0
3 years ago
Sketch the graph of the function by (a) applying the Leading Coefficient Test, (b) finding the zeros of the polynomial, (c) plot
pshichka [43]

Answer:

C

Step-by-step explanation:

If its C I'm sorry That seems correct but I don't know for sure, just my advice!

5 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height
Ilia_Sergeevich [38]

Answer:

\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}

From this point on, you have two possibilities, either you find each individual y_{f}, y_{0}, t_{f}, t_{0} and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

t_{f}-t_{0}=\Delta t

and we also know that:

t_{f}=t_{0}+\Delta t

in order to find the final position, we can substitute this final time into the function, so we get:

y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}

so we can rewrite our formula as:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}

y_{0} will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

y_{0}=29t-22t^{2}

y_{0}=29(1)-22(1)^{2}

y_{0}=7ft

we can substitute it into our average velocity equation:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}

and we also know that the initil time will always be 1, so we can substitute it as well.

\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}

so we can now simplify our formula by expanding the numerator:

\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}

\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}

we can now simplify this to:

\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}

Now we can factor Δt to get:

\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}

and simplify

\overline{v}=-15-22\Delta t

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s

\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s

\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s

\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s

5 0
3 years ago
Solve using substitution.<br> X = -5<br> -3x + y = 19
seropon [69]
Y=4
i hope this helped you
8 0
3 years ago
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