If you are looking for the average it it somewhere around 64
Answer:
The car is slowing down.
Step-by-step explanation:
The graph compares the speed of Sam's car to the time that has passed. In section C, the graph is decreasing; this means the dependent variable, speed, is decreasing as the independent variable, time, is increasing.
His car is slowing down.
Answer:
The equivalent expression for |b| > 2 is {b : b < -2} ∪ {b : b > 2}.
Step-by-step explanation:
The expression |x| < a is equivalent to -a < x < a and the expression |x| > a is equivalent to {x : x < -a} ∪ {x : x > a}.
This means, the set of all points that satisfy the inequality |x| < a is the set of all points between -a and a exclusive of -a and a.
The set of all points that satisfy the inequality |x| > a is the set of all points that are less than -a and the set of all points that are greater than a.
Hence, the equivalent expression for |b| > 2 is {b : b < -2} ∪ {b : b > 2}.
Answer:
The answer is 7x
Step-by-step explanation:
To solve the problem drop the brackets and add the like terms
∵ (4x - 6) + (3x + 6)
- There is no number multiplied by each bracket so drop the
brackets without any change in the values inside them
∴ (4x - 6) + (3x + 6) = 4x - 6 + 3x + 6
- The terms 4x and 3x are like terms, so add them
∵ 4x + 3x = 7x
- The terms -6 and 6 are like terms, so add them
∵ -6 + 6 = 0
∴ 4x - 6 + 3x + 6 = (4x + 3x) + (-6 + 6)
∵ (4x + 3x) + (-6 + 6) = 7x + 0
∴ 4x - 6 + 3x + 6 = 7x
∴ (4x - 6) + (3x + 6) = 7x
The answer is 7x
There is a probability of 22.66% that their average catch is less than 31.5 pounds
<h3>What is
z score?</h3>
The z score is used to determine by how many standard deviations the raw score is above or belaw the mean. It is given by:
z = (raw score - mean)/ (standard deviation ÷ √sample)
Given that, mean = 32, std = 4, sample = 36, hence:
For 31.5:
z = (31.5 - 32) / (4 ÷√36) = -0.75
P(z < -0.75) = 0.2266
There is a probability of 22.66% that their average catch is less than 31.5 pounds
Find out more on z score at: brainly.com/question/25638875
