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2 years ago

HELLLPPPP PLEASEEEEE

Mathematics

2 answers:

kirill [66]2 years ago

8 0

Answer:

About 1,963.50

Step-by-step explanation:

Since we know the whole volume and the height, we need to go backwards.

27,488.94 / 14 = 1,963.50

devlian [24]2 years ago

8 0

Answer:

1,963.50 11

Step-by-step explanation:

it was on my quiz

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Please help and thank you

AlladinOne [14]

Answer:

Step-by-step explanation:

you can locate the points on the graph. 4, 1, 1/2 etc

5 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

Studentka2010 [4]

Answer: a

Step-by-step explanation: its below average

8 0

3 years ago

Read 2 more answers

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass

Semmy [17]

190*(1/2)^4 = 190/16 = 11.875 . . . grams

5 0

2 years ago

Two common names for streets are Second Street and Main Street, with 15,969 streets bearing one of these names. There are 365 m

Helga [31]

8167 streets are named Second Street and 7802 streets are named Main Street.

Step-by-step explanation:

Given,

Total streets = 15969

Let,

x be the number of streets named as Second Streets

y be the number of streets named as Main Streets

According to given statement;

x+y=15969 Eqn 1

x = y+365 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$(y+365)+y=15969\\y+365+y=15969\\2y=15969-365\\2y=15604$

Dividing both sides by 2

$\frac{2y}{2}=\frac{15604}{2}\\y=7802$

Putting y=7802 in Eqn 2

$x=7802+365\\x=8167$

8167 streets are named Second Street and 7802 streets are named Main Street.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

6 0

2 years ago

Convert: 6y + y² = x² from rectangular to polar form.

11Alexandr11 [23.1K]

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\$

$\bf 6y+y^2=x^2\implies \cfrac{6y}{x^2}+\cfrac{y^2}{x^2}=1\implies \cfrac{6rsin(\theta )}{[rcos(\theta )]^2}+\cfrac{[rsin(\theta )]^2}{[rcos(\theta )]^2}=1
\\\\\\
\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies 
\cfrac{6sin(\theta )}{rcos^2(\theta )}+\cfrac{sin^2(\theta )}{cos^2(\theta )}=1$

$\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )
\\\\\\
\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r
\\\\\\
\cfrac{6sin(\theta )}{cos(2\theta )}=r$

5 0

2 years ago