Answer:
The answer is Door you can choose C because is likely to be the answer
System of Equations
For the problem to solve we'll use the following variables:
x = number of the early bird tickets sold
y = number of the regular tickets sold
Haley sold a total of 20 tickets, thus:
x + y = 20 [1]
Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:
10x + 15y = 225
Dividing by 5:
2x + 3y = 45 [2]
We have to solve the system of equations [1] and [2].
Multiply [1] by -2:
-2x - 2y = -40 [3]
Add [3] to [2]:
-2x - 2y +2x + 3y = -40 + 45
Simplifying:
y = 5
Substituting in [1]:
x + 5 = 20
Subtracting 5:
x = 20 - 5
x = 15
Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets
The order pair solution is (15,5)
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
Negative. It’s the only one that makes since. ( probably)
