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3 years ago

What are bonds in metals like? (K12)

Chemistry

2 answers:

elena-s [515]3 years ago

8 0

Answer:

Metallic bonds are the force of attraction between positive metal ions and the valence electrons that are constantly moving around them. The ions form a lattice-like structure held together by the metallic bonds. Metallic bonds explain why metals can conduct electricity and bend without breaking.

Explanation:

Dennis_Churaev [7]3 years ago

3 0

Answer:

I can not answer this question but i can assure you that the other one who has answered is 100% Correct!!! :D

~ Zachary

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The volume of 3.73 moles of a gas is 78.3 L at a certain temperature and pressure. At the same temperature and pressure, the mol

Oksanka [162]

Explanation:

) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? P PV = nRT. 5.6 (12)=460821) T.

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3 years ago

How many atoms are there in total in a molecule of sulfur trioxide, SO3?

viva [34]

Answer:

Explanation:

There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide (mol is the abbreviation for mole).

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3 years ago

Calculate the mass of CaCl2 ( formula wt. = 110.99) thatshould

NNADVOKAT [17]

Answer: 5622.6g

Explanation:

Note: Kf for water is 1.86°C/m.

The simple calculation is in the attachment below.

7 0

3 years ago

10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?

Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles = Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

7 0

3 years ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

7 0

3 years ago