The amount of heat that is required to melt 22g piece of ice at -8 degrees to water at 14 degrees is 1,011.56 Joules.
<h3>How do we calculate the required heat?</h3>
Required amount of heat will be calculated by using the below equation as:
Q = mcΔT, where
m = mass = 22g
c = specific heat of ice = 2.09 J/g. degree C
ΔT = change in temperature = 14 - (-8) = 22 degree C
On putting all values, we get
Q = (22)(2.09)(22) = 1,011.56 J
Hence required amount of heat is 1,011.56 J.
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<span>R= 8.314 J/mol K
T= 273 + 102 = 375K</span><span>
= (3/2) x 8.314 x 375 = 4680 J/mol</span>
Answer:
The temperature should be higher than 437.9 Kelvin (or 164.75 °C) to be spontaneous
Explanation:
<u>Step 1:</u> Data given
ΔH∘=20.1 kJ/mol
ΔS is 45.9 J/K
<u>Step 2:</u> When is the reaction spontaneous
Consider temperature and pressure = constant.
The conditions for spontaneous reactions are:
ΔH <0
ΔS > 0
ΔG <0 The reaction is spontaneous at all temperatures
ΔH <0
ΔS <0
ΔG <0 The reaction is spontaneous at low temperatures ( ΔH - T*ΔS <0)
ΔH >0
ΔS >0
ΔG <0 The reaction is spontaneous at high temperatures ( ΔH - T*ΔS <0)
<u>Step 3:</u> Calculate the temperature
ΔG <0 = ΔH - T*ΔS
T*ΔS > ΔH
T > ΔH/ΔS
In this situation:
T > (20100 J)/(45.9 J/K)
T > 437.9 K
T > 164.75 °C
The temperature should be higher than 437.9 Kelvin (or 164.75 °C) to be spontaneous
B. Carbon dioxide bexause it is 96.5%
Explanation:
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