Answer:
The vertex of the parabola = (-7 , -4)
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the parabola y = 4 x² + 56 x +192
y = 4 (x² + 14 x + 48 )
y = 4 ( x² + 2 × 7 (x) + 49-1)
y = 4 ( x² + 2 × 7 (x) + 49)- 4
we apply the formula
(a +b)² = a² + 2ab + b²
y = 4 ( x + 7 )² - 4
<u>Step(ii):-</u>
<em>The general form of the parabola in algebraically</em>
<em> y = a ( x-h)² +k</em>
<em>The equation </em>
<em> y = 4 ( x + 7 )² - 4</em>
y = 4 ( x-(-7))² - 4
The vertex of the parabola (h,k) = (-7 , -4)
<u>Final answer:-</u>
The vertex of the parabola = (-7 , -4)
1) graphs y = -9x + 12 and y = 1/3x - 12 are not coincident.
2) The graphs are not parallel, because the angular coefficients are not equal
3) The condition of perpendicularity:
, where 
- not perpendicular
First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23