The graph starts flat but then curves steeply upwards. You can tell this by the sudden jumps in y-coordinates, illustrating that it keeps going further up faster and faster as the x-coordinates progress steadily.
Answer: The graph shows exponential decay
The graph shows y = 2^x reflected over the y-axis
Step-by-step explanation:
When<u> 0<b<1 </u>, the graph shows <u>exponential decay</u>. In this case, b was equal to 1/2 as shown by the graph alongside the question. Therefore, the graph shows exponential decay.
The graph of y = 2^x would show a reflection of y = 1/2 ^x over the y-axis, therefore the graph shows <u>y = 2^x reflected over the y-axis</u>.
The slope of the tangent line to 
at 
is given by the derivative of at that point:
Factorize the numerator:
We have 
approaching -1; in particular, this means 
, so that
Then
and the tangent line's equation is
hello since we are simplifying 15^-3*15^6 all we have to do is add the exponents when we add them we end up with an answer of 15^3
To isolate b, add a and subtract c to the entire equation:
D - a + c = -b
Muliply b by -1 to eliminate the negative:
-D + a - c = b
