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weqwewe [10]
3 years ago
13

3. What are two reasons for versioning your still life project file? (1.0 points)

Computers and Technology
1 answer:
inna [77]3 years ago
3 0

Answer:

The project file can be managed by making its multiple version due to the following reasons.

1. We can create multiple copies or version of the project to avoid any unfortunate circumstance such as Project file can be corrupted or can be deleted. In that case we can use the other version of that project file.

2. When we are working on some project, we are modifying the code or program to achieve our desired results. In this process we may forgot the changes that we have made while modification. If we does not obtain our desired results while modification that can lead to losing the original file. To reduce this type of risk we create multiple versions of project File.

3. We also create version of our project files on some internet drives as a backup. In case our computer has lost or operating system has been corrupted. A version of our project file is available on Internet drives such as Google drive or Drop box.

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3.A ball is thrown into the air with an initial velocity of 15 m/s. a.How long does it take the ball to reach maximum height?b.W
ehidna [41]

Answer:  a) = 1.5 sec.  b= 11.5 m. c=0  d= 1.5 sec.

Explanation:

a) Once thrown into the air , the only influence on the ball is gravity, so, we can conclude that the acceleration acting on the ball is the one due to gravity, i.e., g= 9.8 m/sec².

Applying the definition of acceleration, we can write the following equation:

a= (vf-vo) / t   ⇒ g = vf-vo / t. (1)

Now, when the ball reaches to his maximum height, it stops momentarily, and then starts to fall, so for this height, we can write vf=0.

Replacing  in (1), and solving for t, we get:

t = (0 -vo) / g = -15 m/s/ - 9.8 m/sec² (Taking upward as positive  direction)

a) t= 1.5 sec.

Replacing this value in the kinematic equation for displacement, when vo=15 m/s, we get:

hmax: 15 m/sec . 1.5 sec -1/2. 9.8 m/sec². (1.5 sec) ² (2)

b) hmax= 11.5 m

c) vf= 0 (as explained above)

Finally, in order to know how long the ball takes to return to its initial height, we know that for the falling part of the trajectory, vo=0, so we can write the equation for displacement as follows:

h=-hmax (because it returns to the same starting point)= 1/2 gt²=-11.5 m

Solving for t, we get:

d) t=1.5 sec.

It can be seen that the time used in going up, it is the same for going down, to travel the same distance.

This result is completely general and applies to any free fall problem.

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operators to organize the students' grades, then

operators to compare the results."

i think your right

Explanation:

sounds right.

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