3. What are two reasons for versioning your still life project file? (1.0 points)

Computers and Technology

1 answer:

inna [77]3 years ago

3 0

Answer:

The project file can be managed by making its multiple version due to the following reasons.

1. We can create multiple copies or version of the project to avoid any unfortunate circumstance such as Project file can be corrupted or can be deleted. In that case we can use the other version of that project file.

2. When we are working on some project, we are modifying the code or program to achieve our desired results. In this process we may forgot the changes that we have made while modification. If we does not obtain our desired results while modification that can lead to losing the original file. To reduce this type of risk we create multiple versions of project File.

3. We also create version of our project files on some internet drives as a backup. In case our computer has lost or operating system has been corrupted. A version of our project file is available on Internet drives such as Google drive or Drop box.

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C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}

Sample Input/Output is attached