Answer:
<u>Given circle:</u>
The center is at (4, 0) and the radius is 5 units
<u>Lets find the distance from (7, 2) to the center of the circle:</u>
- <u />
![d = \sqrt{(7 - 4)^2 + (2 - 0)^2} = \sqrt{9+4} = \sqrt{13} < 5](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%287%20-%204%29%5E2%20%2B%20%282%20-%200%29%5E2%7D%20%20%3D%20%5Csqrt%7B9%2B4%7D%20%3D%20%5Csqrt%7B13%7D%20%3C%205)
Since d < 5, the point (7, 2) lies <u>inside</u> the circle
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Plot the y-intercept (0,-1) and then from that point go up seven and to the right one. Plot that point, then draw the line between the two points.
Hope this helped! Good luck! :)
So first Isolate the variable by dividing each side by factors that don't contain the variable.
y= 3x/2 + 3
Hope this helps!
Answer:
75%
Step-by-step explanation: