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3 years ago

consider the function f(x)=5(x+2)^(2)-3 which of the following function shifts the gragh of (x) upward by 4 units

Mathematics

1 answer:

ivolga24 [154]3 years ago

8 0

Answer:

$g(x)=5(x+2)^2+1$

Step-by-step explanation:

The given function is $f(x)=5(x+2)^2-3$ .

Let the new function be g(x).

Then g(x) is obtained by shifting f(x) up by 4 units.

This implies that: $g(x)=f(x)+4$

$g(x)=5(x+2)^2-3+4$

$g(x)=5(x+2)^2+1$

Hence the new function is $g(x)=5(x+2)^2+1$

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Evelyn has dance class every Saturday. It lasts 1 hour and 40 minutes and is over at 12:45 P.M.

leva [86]

Answer:

Evelyn's dance class on Saturday starts at 11:05 A.M.

Step-by-step explanation:

I know this because if her class takes an hour and 40 minutes you would subtract the hour and 40 minutes from 12:45 so you could do 12 - 1 which equals 11. Then you would do 45 - 40 which equals 5. And last you would put the new times together so it would be, 11:05. Her dance class starts at 11:05 A.M.

7 0

3 years ago

For the first 80 miles of her road trip, Lina travels 10 miles/hour slower than she did for the remaining 50 miles of her trip.

Contact [7]

The expressions represent the total time of her trip in hours is $\rm \dfrac{80}{s} + \dfrac{50}{s+10}$ .

Given that,

For the first 80 miles of her road trip, Lina travels 10 miles/hour slower than she did for the remaining 50 miles of her trip.

It represents Lina's speed during the first part of her trip.

We have to determine,

Which expressions represent the total time of her trip in hours?

According to the question,

Let the speed traveled during the first part of the trip be "s".

The formula for calculating the distance is expressed as:

$\rm Distance = Speed \times Time$

For the first part of the journey:

Distance = 80 miles

Time = $\rm t_1$

And Speed = s

Substitute all the values in the formula,

$\rm Distance = Speed \times Time\\\\80 = s \times t_1\\\\ t_1= \dfrac{80}{s}$

For the second part of the trip;

Distance traveled = 50 miles

Speed = s + 10 (10miles/hour faster than the first part of the trip)

time = $\rm t_2$

Substitute all the values in the formula,

$\rm Distance = Speed \times Time\\\\50 = (s+10) \times t_2\\\\ t_2 = \dfrac{50}{s+10}$

Therefore,

Adding both the time to represent the total time of her trip in hours,

$\rm = t_1 +t_2 \\\\ = \dfrac{80}{s} + \dfrac{50}{s+10}$

Hence, The required expressions represent the total time of her trip in hours is $\rm \dfrac{80}{s} + \dfrac{50}{s+10}$ .

For more details refer to the link given below.

brainly.com/question/21043759

6 0

2 years ago

What is the mixed number form<br> of 33/8

goblinko [34]

HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8

4 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (1, 3) and (5, –2)?

Sergeu [11.5K]

m=-(5/4)

From left to right, (1,3) is first and then comes (5,-2). Always remember when finding slopes without equations, the rule is RISE over RUN, to the numerator and denominator, respectively.

The y value of the second coordinates becomes negative which is unlike the y value in the first coordinates, which means our slope is downward, meaning it has a negative sign in front.

In every slope, there’s a numerator, being the rise, and a denominator, being the run.

To find the rise, we must look at the y values. Starting at 3 going to -2 has a space of 5 units, making that our numerator.

To find the run, the first x value is 1 and the second is 5, making a space of 4, which is out denominator.

With these two numbers and the negative sign, we get -(5/4) as our slope.

7 0

3 years ago

Given the following functions f(x) and g(x), solve f[g(10)] and select the correct answer below: f(x) = 10x + 8 g(x) = x + 9 2,0

ikadub [295]

ANSWER
$f(g(10)) = 198$

EXPLANATION

The given functions are;

$f(x) = 10x + 8$
and

$g(x) = x + 9$

To find
$f(g(10))$
we need to find

$f(g(x)) = f(x + 9)$

$f(g(x)) =10(x + 9) + 8$

$f(g(x)) =10x + 90 + 8$

$f(g(x)) =10x + 98$

$f(g(10)) = 10(10) + 98$

$f(g(10)) = 100 + 98$

$f(g(10)) = 198$

The last option is the correct answer

7 0

3 years ago

Read 2 more answers