Answer:
$751
Explanation:
From the question we have the following information;
Gross income = $1000.00
Deductions = $294.00
Now we know that;
Net income = Gross income - Deductions
Therefore;
Net income = $1000.00 - $294.00
Net income = $751
the reason HTML seems to work even if it has syntax errors is due to browser having built in ways to parse the code meaning it will still show but most likely look way different then you would want.
the code may turn pink due to syntax errors
Answer:
general regulatory and speed control.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
Answer:
3 bits
Explanation:
Given a 4- way set associative cache that has 64 blocks of 16 words.
Therefore, the number of sets cache has:
Now,
Cache data size is 16kB
The number of cache blocks can be calculated as:
Now,
Total sets = 
Total sets = 
Now,
n = 6
For 15 bit address for the architecture, the bits in tag field is given by:
15 - (6 + 6) = 3 bits
Thus the tag field will have 3 bits
