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Katarina [22]
3 years ago
6

Which type of document would be best created in Word? HELLP!!!!

Computers and Technology
2 answers:
bekas [8.4K]3 years ago
8 0
I think it’s presentation.
Like if I am right.
IRISSAK [1]3 years ago
8 0

Answer: The answer is Resume

Explanation: I had this question on a quiz of mine and got the question right! Trust me it’s the right answer

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What does median mean in the data?
QveST [7]

Answer:

What data? Also, if it's median wouldn't that be Mathematics? edit-im sorry im d-u-m-b i thought you meant there was numbers and data but you mean the meaning of median

the median in data is the middle number and if its an even number you add the two middles together and divide by two

again sorry

4 0
3 years ago
Read 2 more answers
When was the speaker invented?
wlad13 [49]

Answer:

Explanation:

1876

4 0
3 years ago
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"Common knowledge" must always be credited or else it is considered plagiarism?<br> True<br> Fales
igomit [66]
Hi!

It depends on how close you have paraphrased it. If your "common knowledge" is very closely related to the resource, it would be considered plagiarism.
3 0
3 years ago
Write a for loop that sets each array element in bonusScores to the sum of itself and the next element, except for the last elem
Nat2105 [25]

Answer:

The program to this question can be given as:

Program:

#include<stdio.h>  //header file.

int main()

 //main function

{

   int SCORES_SIZE = 4;  //define variables.

   int bonusScores[]={10,20,30,40};  //define array.

   int i;

   printf("Values:");

 //message

   for (i = 0; i < SCORES_SIZE; ++i)  //loop for print values.

   {

       printf("%d ", bonusScores[i]);

   }

void CombineScores(int numberScore, int userScore) //function

{

   for (i = 0; i < SCORES_SIZE; i++)

  //loop for convert values

   {

       if (( bonusScores[i] <= bonusScores[i +1] ) || (bonusScores[i] < bonusScores [i+1]))  //check array elements

       {

           bonusScores[i] = (bonusScores [i] + bonusScores[i+1]);

 //add values

       }

       else

       {

           bonusScores[i] = bonusScores[i];

       }

   }

   printf("\nReturn values:");  //message

 for (i = 0; i < SCORES_SIZE; i++)

{

printf("%d",bonusScores[i]);

}

}

CombineScores(0,0); //calling

return 0;

}  

Output:

Values:10 20 30 40  

Return values:30 50 70 40  

Explanation:

In the above c++ programming code firstly we define the header file. Then we define the main function in this function we define variable that name is given in the question that is SCORES_SIZE, i. Variable i is used in the loop for a print array. Then we define and initialize an array. The array name is and elements are define in the question that is bonusScores[]={10,20,30,40}. Then we use the loop for print array elements.Then we define function that is CombineScores() in this we pass two parameter. Then we use the second time in this loop we check array elements and add the elements that are given in the question. In this function we print values and at the end we call function.

3 0
3 years ago
Create a Boolean function odd_number_digits(n) that returns True when a positive integer has an odd number of digits. (You may a
Snowcat [4.5K]

Answer:

Following are the code to this question:

import java.util.*;//import package for user input

public class Main//defining class main

{

   public static boolean odd_number_digits(int n)//defining boolean method odd_number_digits

   {

       if(n>0 && n%2!=0)//defining if block that check value is positive and odd number

       {

       return true;//return value true

       }

       else//defining else block

       {

           return false;//return false value

       }

   }

   public static void  sum_odd_digits(int n)//defining a method sum_odd_digits

   {

       int sum=0,i;//defining integer variable

       for(i=0;i<=n;i++)//defining for loop

       {

           if(i%2!=0)//defining if block for odd number

           {

               sum=sum+i;//add odd number

           }

       }

      System.out.print(sum);//use print method to print sum value

   }

public static void main(String[] args) //defining main method

   {

       Scanner ox=new Scanner(System.in);//creating Scanner object

       int n= ox.nextInt();//defining integer variable for input value

       System.out.print(odd_number_digits(n)+ "\n");//use print method to call method

       System.out.println("Sum of odd numbers: ");//print message

       sum_odd_digits(n);//calling method

   }

}

Output:

please find the attachment.

Explanation:

In the above code, two methods "odd_number_digits and sum_odd_digits" are defined in which the first method return type is boolean because it will true or false value, and the second method returns the sum of odd numbers.

In the "odd_number_digits" method,  an integer variable passes as an argument and inside the method, if block is used that check value is a positive and odd number then it will return a true value.

In the "sum_odd_digits" method, it accepts an integer parameter "n", and define integer variable "sum" inside the method, which uses the for loop, inside the loop if block is used that counts odd numbers and adds its in sum and print its value.

8 0
3 years ago
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