Answer: 19.8 ft
Step-by-step explanation:
Use the Pythagorean Theorem formula to solve for how high the top of the ladder reach.
The formula says a^2 + b^2 = c^2
Where a and b are the two legs and C is the hypotenuse.
In this situation, the hypotenuse will be length of the ladder , and either a or b will be the length of the ladder from the building or the length of how long the ladder.
a will be 3 , and c will be 20. Input in the values into the formula and solve for b.
3^2 + b^2 = 20^2
9 + b^2 = 400
-9 -9
b^2 = 391
b = 
b = 19.77371 round to the nearest tenth is , 19.8
Answer:
.125
Step-by-step explanation:
Answer:
No Solutions.
Step-by-step explanation:
I will solve your system by substitution.
3y−3=3x; −3x+3y=−57
Step: Solve 3y−3=3x for y:
3y−3+3=3x+3 (Add 3 to both sides)
3y=3x+3
(3y/3=3x+3)/3
(Divide both sides by 3)
y=x+1
Step: Substitute x+1 for y in −3x+3y=−57:
−3x+3y=−57
−3x+3(x+1)=−57
3=−57 (Simplify both sides of the equation)
3+(−3)=−57+(−3) (Add -3 to both sides)
0=−60
<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
