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3 years ago

Can someone help explain how to solve this problem please? It would be very helpful.

Mathematics

1 answer:

ladessa [460]3 years ago

7 0

Z=180-84-50
x=180-84-63
y=180-33-13

z=46
x=33
y=134

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Select the conic section that represents the equation. y2 = 10x circle ellipse parabola hyperbola

Makovka662 [10]

The conic that represents the equation y² = 10x is a parabola

Step-by-step explanation:

The general equation for any conic section is

Ax² + Bxy + Cy² + Dx + Ey + F = 0, where A, B, C, D, E and F are

constants

1. If B² - 4AC < 0, if a conic exists, it will be either a circle or an ellipse,

if A and C are equal then it is a circle, if not then it is an ellipse

2. If B² - 4AC = 0, if a conic exists, it will be a parabola

3. If B² - 4AC > 0, if a conic exists, it will be a hyperbola

∵ The equation is y² = 10x

- Subtract 10x from both sides

∴ y² - 10x = 0

∴ A = 0 , B = 0 , C = 1 , D = -10 , E = 0 and F = 0

∵ B² - 4AC = (0)² - 4(0)(1) = 0

∴ B² - 4AC = 0

∴ The conic is parabola

The conic that represents the equation y² = 10x is a parabola

Learn more:

You can learn more about discriminant in brainly.com/question/8196933

#LearnwithBrainly

6 0

3 years ago

A hemisphere has an area of 256 pi cm^2. What is its volume?

Amanda [17]

$\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\$

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}$

7 0

3 years ago

Hurry and help please

vivado [14]

Answer:

Number 1 does not 2 and 3 do

Step-by-step explanation:

This is because 1 doesn't pass the vertical line test but 2 and 3 do

6 0

3 years ago

Help please!!!!!!!!!!

djyliett [7]

Try A and see if it works but im not sure

3 0

3 years ago

The tickets for the school play are $7.00 for adults and $5.00 for students. There were 100 tickets sold. If the total profit wa

inessss [21]

Answer:

25 adult tickets and 75 student tickets were sold.

Step-by-step explanation:

Given that the tickets for the school play are $ 7.00 for adults and $ 5.00 for students, and that there were 100 tickets sold generating a total profit of $ 550.00, to determine how many of each were sold the following calculation must be performed:

100 x 5 = 500

550 - 500 = 50

7 - 5 = 2

50/2 = 25

100 - 25 = 75

(25 x 7) + (75 x 5) = X

175 + 375 = 550

Therefore, 25 adult tickets and 75 student tickets were sold.

5 0

3 years ago