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docker41 [41]
3 years ago
12

Need help help for 30 points

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0
100x24 because u have to count the shaded squares
S_A_V [24]3 years ago
4 0
100 times 17 bc u have to count the shdded parts
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Can you find the area for this?
Tanzania [10]

Answer:

b. is the right answer of your question

8 0
3 years ago
Read 2 more answers
If g( n ) = 3 n - 2, then what is the value of g(10)?<br><br> 4<br> 28<br> 308<br> 24
tino4ka555 [31]

Answer:

28

Step-by-step explanation:

g(10)=3n-2

10=n

3(10)-2

REMEMBER PEMDAS

Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction.

3(10)=30

30-2=28

Hope this helps have a wonderful evening!

8 0
3 years ago
You lose an online auction for an autograph. Your losing bid of $28 is 40% of the winning bid. How much less was your bid than t
TEA [102]

Answer:

My bid was $42 less than the winning bid.

Step-by-step explanation:

The winning bid is x.

$28 is 40% of x

0.4x = 28

x = 28/0.4

x = 70

The winning bid was $70.

$70 - $28 = $42

Answer: My bid was $42 less than the winning bid.

5 0
2 years ago
Krutika and Natasha win some money and share it in the ratio 1:2. Krutika gets £8. How much did they win in total?
Inessa [10]

Answer:£24

Step-by-step explanation:

Let the total money be represented by Y

Total ratio =1+2=3

Krutika's share =1/3 × Y

8= 1/3×Y

Y=8÷(1/3)

Y= 8×3

Y=£24

The total Money they won was 24

6 0
3 years ago
The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum
boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

<em>Let represent the annual energy consumption of the town as E</em>

<em>The rate of annual energy consumption *  energy consumption at time past</em>

<em>dE/dt * E</em>

<em>dE/dt =K</em>

<em>k = the proportionality constant</em>

<em>c= the integration constant</em>

<em>(dE/dt=) kdt</em>

<em>lnE = kt + c</em>

<em>E(t) = e^kt+c ⇒ e^c e^kt  e^c is a constant, and e^c = E₀</em>

<em>E(t) = E₀ e^kt</em>

<em>The initial consumption of energy is E(0)=4.4TBTU</em>

<em>set t = 0 then</em>

<em>4.4 = E₀ e⇒ E₀ (1) </em>

<em>E₀ = 4.4</em>

<em>E (t) = 4.4e^kt</em>

<em>The consumption after 5 years is t = 5, e(5) = 5.5TBTU</em>

<em>so,</em>

<em>E(5) = 5.5 = 4.4e^k(5)</em>

<em>e^5k = 5/4</em>

<em>We now take the log 5kln = ln(5/4)</em>

<em>5k(1) = ln(5/4)</em>

<em>k = 1/5 ln(5/4) = 0.04463</em>

<em>We find  the town's annual energy consumption, after 9 years</em>

<em>we set t=9  </em>

<em>E(9) = 4.4e^0.04463(9)</em>

<em>= 4.4(1.494301) = 6.5749TBTUs</em>

<em>Therefore the annual energy consumption of the town after 9 years is </em>

<em>= 6.575 trillion BTUs</em>

<em />

3 0
3 years ago
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