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3 years ago

Please hurry!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

sasho [114]3 years ago

7 0

Answer:

Your question is not proper.Here, you said that range of data. But where is the data? How can you expect answer without giving proper question?

Alex3 years ago

3 0

Answer:

Step-by-step explanation:

Range is the largest number minus the smallest number

55-17=38

I hope I hurried enough

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What is 1/3 of a kilometer

marissa [1.9K]

= (1/3) * 1000 meters
= 333.33 meters
OR
=.3333333 kilometers

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3 years ago

A theme park designer wants to build a water slide with a slope of -3. The slide has to end at (120, 0). What is a possible star

stiks02 [169]

Answer:

Step-by-step explanation:

if the slope is -3 the y intercept will be (0,360). thus that is the best answer choice.

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3 years ago

Coins are marked with the letters A-G. What is the probability of selecting a coin with a vowel on it?

Lemur [1.5K]

A B C D E F G.

Out of these, 2/7 letters are vowels.

2 / 7 ≈ 0.286
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4 years ago

Read 2 more answers

Camila sets up a passcode on her tablet, which allows only nine-digit codes. A spy sneaks a look at Camila's tablet and sees her

laila [671]

Answer:

$\frac{1}{10^9}$ probability the spy is able to unlock the tablet on his first try.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

1 correct password, so $D = 1$

Total outcomes:

Nine-digit codes.

For each digit, there are 10 possible outcomes. So

$T = 10^9$

What is the probability the spy is able to unlock the tablet on his first try?

$p = \frac{D}{T} = \frac{1}{10^9}$

$\frac{1}{10^9}$ probability the spy is able to unlock the tablet on his first try.

7 0

3 years ago

(10x^3y^-2/5x^-3y^4)^-3, x≠0, y≠0

zhenek [66]

Answer:

$\dfrac{y^{18}}{8x^{18}}$

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

(a^b)^c = a^(bc)

Your expression simplifies as follows:

$\left(\dfrac{10x^3y^{-2}}{5x^{-3}y^4}\right)^{-3}=(2x^{3-(-3)}y^{-2-4})^{-3}=(2x^6y^{-6})^{-3}\\\\=(2^{-3})x^{6(-3)}y^{(-6)(-3)}=\dfrac{1}{8}x^{-18}y^{18}\\\\=\boxed{\dfrac{y^{18}}{8x^{18}}}$

6 0

4 years ago