Given:
A number is 400.
To find:
The additive inverse of 400.
Solution:
We know that the sum of a number and its additive inverse is 0.
If "a" is number and "b" is its additive inverse, then
Let x be the additive inverse of 400. Then,
Subtract both sides by 400.
Therefore, the additive inverse of 400 is 
.
Answer:
free answer
Step-by-step explanation:
it is free
9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
10x - 4y = 5 (if it requires shorten)
Step-by-step explanation:
x + y/5 - 1 = y - x
<=> (5x + y - 1.5)/5 = 5(y - x)/5
<=> 5x + y - 5 = 5y - 5x
<=> 5x + 5x + y - 5y = 5
<=> 10x - 4y = 5
The properties that apply true are:
1–as it implies the Pythagorean theorem; a^2+b^2=c^2
3–as it implies the basic rules of visualized geometry.
4–as the greater side(hypotenuse) is opposite the right angle.
NOT 2, as the accrue angles ARE complimentary.
