Given:
The graph of a line.
To find:
The point-slope form of the given line.
Solution:
From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:
The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:
Therefore, the point-slope form is , slope is 6 and the point is (1,5).
You want log √(9/25). Recognizing that √9 = 3 and that √25 = 5, we get
log 3/5, which by rules of logs comes out to log 3 - log 5.
To four decimal places:
log 3 - log 5 = 0.4771 - 0.6990, or -0.2218.
Answer:
f
(
x
)
=
5
x
2
−
2
x
+
3
g
(
x
)
=
4
x
2
+
7
x
−
5
f
(
g
(
x
)
)
=
5
(
4
x
2
+
7
x
−
5
)
2
−
2
(
4
x
2
+
7
x
−
5
)
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
350
x
+
125
−
8
x
2
−
14
x
+
10
+
3
=
80
x
4
+
280
x
3
+
45
x
2
−
8
x
2
−
350
x
−
14
x
+
125
+
10
+
3
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
The answer is
f
(
g
(
x
)
)
=
80
x
4
+
280
x
3
+
37
x
2
−
364
x
+
138
.
Step-by-step explanation:
Divide 4 on both sides. and the answer is X= -7
now, we know the tangent line at (2,4) is y = 8x - 12, now, that's already in slope-intercept form, so, the slope of that tangent at (2,4) is "8" then.
now, that means when x = 2, the slope is 8, so let's use that.
