Solve for x !!!! Please help mee

Mr.george owns 425 acres of land.if he divides the land into half-acre plots,how many plots will he have?

tatiyna

850
All you do is times 425 by 2
425×2
850
hope this helps

6 0

3 years ago

120 students of a hostel food enough for 60 days. if 30 more students joined after 15 days. how long will the remaining food las

JulsSmile [24]

Answer:

24 days

Step-by-step explanation:

120 students =30 days

120+30 =150 students

MORE/LESS METHOD

120 students (a) : 30 days(y)

150 students (b) : x

Find the value of x using the formula: a/b × y

If you think the value of x will be more than y then the bigger number will be the numerator. If u think x will be less, then the smaller number will be in the numerator.

I predict that x will be less than y

THEREFORE... 120/150 ×30

= 24 days

8 0

3 years ago

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Solve the equation x + 0.7 = 1 - 0.2x in two different ways.Then check your answer.Show your work!

expeople1 [14]

Simplifying
x + 0.7 = 1 + -0.2x

Reorder the terms:
0.7 + x = 1 + -0.2x

Solving
0.7 + x = 1 + -0.2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.2x' to each side of the equation.
0.7 + x + 0.2x = 1 + -0.2x + 0.2x

Combine like terms: x + 0.2x = 1.2x
0.7 + 1.2x = 1 + -0.2x + 0.2x

Combine like terms: -0.2x + 0.2x = 0.0
0.7 + 1.2x = 1 + 0.0
0.7 + 1.2x = 1

Add '-0.7' to each side of the equation.
0.7 + -0.7 + 1.2x = 1 + -0.7

Combine like terms: 0.7 + -0.7 = 0.0
0.0 + 1.2x = 1 + -0.7
1.2x = 1 + -0.7

Combine like terms: 1 + -0.7 = 0.3
1.2x = 0.3

Divide each side by '1.2'.
x = 0.25

Simplifying
x = 0.25

I only know 1 way.

6 0

4 years ago

3. Which expression is equivalent to log532?

saul85 [17]

Answer: The Nth power xN of a number x was originally defined as x multiplied by itself, until there is a total of N identical factors. By means of various generalizations, the definition can be extended for any value of N that is any real number.

(2) The logarithm (to base 10) of any number x is defined as the power N such that

x = 10N

(3) Properties of logarithms:

(a) The logarithm of a product P.Q is the sum of the logarithms of the factors

log (PQ) = log P + log Q

(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors

log (P / Q) = log P – log Q

(c) The logarithm of a number P raised to power Q is Q.logP

log[PQ] = Q.logP

Step-by-step explanation:

8 0

3 years ago

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

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