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3 years ago

11

Find the value of x in the isosceles triangle shown below

2 answers:

RUDIKE [14]3 years ago

7 0

The answer is X= 5. Using the pythagorean theorem, and assuming that "b" is 3, half of 6 because the triangle is isosceles, you can solve the problem.

gogolik [260]3 years ago

4 0

Hello!

The answer to this problem is b. × = 5

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kondaur [170]

5x^2 - 24x + 8 is your answer to this equation

4 0

3 years ago

Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model

Varvara68 [4.7K]

Answer:

$Amber = 0$

$Grace = 0.60$

$Marsha =1.70$

Step-by-step explanation:

Given

<em>Decimal Grid = Hundredths</em>

$Amber = None$

$Grace = \frac{3}{5}th$

$Marsha = 1 + \frac{7}{10}th$

To solve for each:

We have:

For Amber:

$Amber = 0 * 100$

$Amber = 0$

For Grace:

$Grace = \frac{3}{5}th$

$Grace = \frac{3}{5} * 100$

$Grace = \frac{300}{5}$

$Grace = 60$

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

$Grace = 60 * \frac{1}{100}$

$Grace =\frac{60}{100}$

$Grace = 0.60$

For Marsha:

$Marsha = 1 + \frac{7}{10}th$

$Marsha = \frac{10 + 7}{10}th$

$Marsha = \frac{17}{10}th$

$Marsha = 1.7th$

Multiply this by 100, to get the number of shaded

$Marsha = 1.7 * 100$

$Marsha = 170$

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

$Marsha = \frac{170}{100}$

$Marsha =1.70$

5 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

Repeated addition: 1 3 + 1 3 + 1 3 = a b a = b =

IgorLugansk [536]

Answer:

39

Step-by-step explanation:

13 + 13 + 13 = 39

13 · 3 = 39

5 0

3 years ago

Read 2 more answers

2. The product of an even number and an odd number is an even number.

ASHA 777 [7]

Answer:

5

Step-by-step explanation:

ok thanks

4 0

3 years ago

Read 2 more answers