Answer:

Step-by-step explanation:
hope this helps
We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=

. Hence CM=GC+GM=3*

. Now, since GM is normal to AB, we have by the pythagoeran theorem that:

Hence, we calculate from this that AC^2= 28, hence AC=2*

=BC. Thus, the perimeter of the triangle is 2+4*

.
Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
a) true
b) false
c) true
Step-by-step explanation:
<h3>let's determine the first statement</h3><h3>to determine x-intercept </h3><h3>substitute y=0</h3>
so,
8x-2y=24
8x-2.0=24
8x=24
x=3
therefore
the first statement is <u>true</u>
let's determine the second statement
<h3>to determine y-intercept </h3><h3>substitute x=0</h3>
so,
8x-2y=24
8.0-2y=24
-2y=24
y=-12
therefore
the second statement is <u>False</u>
to determine the third statements
<h3>we need to turn the given equation into this form</h3><h2>y=mx+b</h2><h3>let's solve:</h3>
8x-2y=24
-2y=-8x+24
y=4x-12
therefore,
the third statement is also <u>true</u>