My question is what is 4-5h how do you solve this problem

Mathematics

2 answers:

Murrr4er [49]3 years ago

5 0

Set the expression equal to 0.
4 - 5h = 0

Add 4 on both sides.
5h = 4

Divide by 5 on both sides.
h = $\fbox {4/5}$

ioda3 years ago

3 0

Let us assume that 4 - 5h = 0

we need to the value of h.

4 - 5h = 0
-5h = -4
-5h/-5 = -4/-5
h = 4/5

To check: substitute h by its value.
4 - 5h = 0
4 - 5(4/5) = 0
4 - 20/5 = 0
4 - 4 = 0
0 = 0

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PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

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$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the denominator:

$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

Simplify:

$4x^{3}$

-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.