Answer:
43 46 34 98 78 67
Step-by-step explanation:
Simplify them until they can be simplified no more, then compare both sides.
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
144 m^3
Step-by-step explanation:
Please find attached the image of the prisms
Volume of a triangular prism = area of the base x height of the prism
Area of the base = 1/2 ( base x height)
the two prisms are similar, thus, the dimensions of the bigger rectangle can be gotten from the ratio of the base of the smaller and bigger triangle
ratio of their dimensions = 6 / 1.5 = 4
the dimensions of the bigger triangle is 4 times that of the smaller triangle
height of the base of the prism = 1.5 x 4 = 6
Height of the prism = 2 x 4 = 8
Area of the base of the prism = (1/2) x 6 x 6 = 18 m^2
Volume of the prism = 18 x 8 = 144 m^3
Let
R = Ralph's age
S = Sara's age
First statement is translated as:
S = 3R
Second statement is translated as:
S + 4 = 2(R + 4)
Use the first equation to be substituted into the second one in terms of R which is the one we are actually going to solve for Ralph's age.
Since S = 3R, then
3R + 4 = 2(R + 4)
3R + 4 = 2R + 8
3R - 2R = 8 - 4
R = 4 years old
