Answer:
of quinoa,
of flaxseed,
of soy protein.
Step-by-step explanation:
<h3>
The missing table is attached.</h3>
Let be "q" the amount of cups of quinoa you'd need to use making the granolas with 3 cups of oats.
Based on the table you can write the following proportion:

Solving for "q", you get:

Let be "f" the amount of cups of flaxseed you'd need to use making the granolas with 3 cups of oats.
With the data given in the table you can write the following proportion:

Solving for "f", you get:

Let be "s" the amount of cups of soy protein you'd need to use making the granolas with 3 cups of oats.
Using the table you can write this proportion:

Solving for "s", you get:

Answer:
x = 24 makes the original equation true
Step-by-step explanation:
2 < x ≤ 24
2 < x signifies x cannot be equal to 2
x≤24 signifies x can be equal to 24.
Answer:
The 500 mice would be the carrying capacity of the field being studied.
Step-by-step explanation:
For the first year of study, the mouse population demonstrates exponential growth.
But by third year, the mouse population has stabilized at approximately 500 mice.
Thus, this 500 mice would be the carrying capacity of the field being studied.
Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.
Answer:
A weak negative correlation
Step-by-step explanation:

where,



This represents a weak negative correlation