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Mathematics

2 answers:

marin [14]3 years ago

6 0

e p i c

im here before this gets reported :P

VLD [36.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

Its symbols from ancient Egypt welded in to the rock that the gods had walked on

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What is the measurement of angle B

Liono4ka [1.6K]

Angles B and D are congruent so:

(360-112-74)/2=87°

6 0

2 years ago

Read 2 more answers

I'd appreciate it if anyone could help! :)<br><br> Which graph represents the function?

Monica [59]

Answer: Upper right corner

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How I got that answer:

The line y = x goes through (0,0) and (1,1). You would normally extend this line out as far as you can in both directions. However, the inequality x < -1 says you can only graph this if x is less than -1. We will not graph any part of the graph that is beyond x = -1 to the right. So we only have a small piece of it. The left piece of y = x. There is an open hole at the endpoint.

Similarly, y = -x is only graphed if x >= -1. We have a closed endpoint here. This graph goes through (0,0) and (1,-1). We erase the portion that is to the left of x = -1.

Doing all this leads to the upper right corner choice as our answer. The bottom right corner is close to the answer, but the open and closed endpoints are in the wrong spots.

3 0

3 years ago

NEED ANSWER ASAP REALLY IMPORTANT i will take any of the answers

dedylja [7]

$1. \: MC \: is \: tangent \: to \: (B)\Rightarrow \widehat{BCM}=90° \\ 2. \: MC \: and \: MZ \: are \: tangent \: to \: (B)\Rightarrow MC = MZ\Leftrightarrow 5x - 9 = x + 7\Leftrightarrow x = 4 \\ 3. \: BM = \sqrt{ {BC}^{2} + {MC}^{2} } = \sqrt{ {5}^{2} + {12}^{2} } = 13 \\ \Rightarrow EM = BM - BE = BM - BC = 13 - 5 = 8 \\ 4. \: \tan(60°) = \frac{MC}{BC} = \frac{13 \sqrt{3} }{ BC}\Leftrightarrow BC = \frac{13 \sqrt{3} }{\tan(60°)} = \frac{13 \sqrt{3} }{ \sqrt{3} } = 13 \\ 5. \: MC = \sqrt{ {BM}^{2} - {BC}^{2} } = \sqrt{ {20}^{2} - {12}^{2} } = 16 \\ 6. \:BZ = \sqrt{ {BM}^{2} - {MZ}^{2} } = \sqrt{ {25}^{2} - {20}^{2} } = 15 \\ \Rightarrow XE=BX+BE=BZ+BZ=15+15=30$