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oksian1 [2.3K]
3 years ago
7

Help me do this question ​

Mathematics
1 answer:
pshichka [43]3 years ago
3 0

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Solve. -2(7 + 8p) = 18 - 8p
Shalnov [3]
The answer is p = -4
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4 years ago
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Luis set up an A-frame ladder so that the angle formed between each side of the ladder and the ground is 125 degrees. What is th
Firlakuza [10]

Answer:

70°

found by considering A-frame ladder as a triangle

Step-by-step explanation:

Given that,

angle form on either side of A-frame ladder with the ground = 125°(exterior)

As it is a A-frame ladder so its a triangle, we will find the angle at the top of ladder by using different properties of triangle

1) find interior angle form by A-frame ladder with the ground

125 + x = 180         sum of angles on a straight line

x = 180 - 125

x = 55°

2) find the angle on top of ladder

55 + 55 + y = 180        sum of angle of a triangle

110 + y = 180

y = 180 - 110

y = 70°

3 0
4 years ago
What is the area of a parallelogram with a base of 4cm and a height of 10 cm ?
Ahat [919]

Answer:

4x10=40 =40cm^2

Step-by-step explanation:

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4 years ago
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En la primera fase del proceso selectivo para Al cuerpo de profesores eliminan a cuatro novenos De los aspirantes mientras que e
irina1246 [14]

Answer:

The fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

Step-by-step explanation:

The question is:

In the first phase of the selection process for the body of teachers they eliminate four-ninth of the applicants while in the second phase they eliminate 5/7 of those who passed the first phase. If there were 315 applicants what is the fraction of the applicants who have passed the two phases of the selection process?

The total number of applicants is

<em>N</em> = 315.

It is provided that 4/9th of the applicants were eliminated in the first phase.

Then the fraction of candidates who passed the first phase is:

Fraction who passed phase I = 1-\frac{4}{9}=\frac{5}{9}

Now, it is also provided that 5/7 of those who passed the first phase were eliminated in the second phase.

Then the fraction of candidates who passed the second phase is:

Fraction who passed phase II = 1-\frac{5}{7}=\frac{2}{7}

That is, 2/7 of the remaining applicants passed the second phase.

The fraction of the applicants who have passed the two phases is:

\frac{5}{9}\times \frac{2}{7}=\frac{10}{63}

Thus, the fraction of the applicants who have passed the two phases of the selection process is \frac{10}{63}.

8 0
3 years ago
What is 52divided by 8
scoray [572]
The answer to 52\8 is 6.5.
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