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Phoenix [80]
3 years ago
15

Subject of the exercise by Bernard maclaverty

English
2 answers:
jasenka [17]3 years ago
6 0
Are there any options?
Iteru [2.4K]3 years ago
3 0
Are there any options to pick from?
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\setlength{\unitlength}{2.5mm}\begin{picture}(10,10)\multiput(0,0)(2,0){21}{\line(0,1){40}}\multiput(0,0)(0,2){21}{\line(1,0){40}}\linethickness{0.45mm}\put(20,20){\vector(2,0){18}}\put(20,20){\vector(-2,0){18}}\put(20,20){\vector(0,2){18}}\put(20,20){\vector(0,-2){18}}\multiput(19.35,6)(0,2){15}{\line(1,0){1.3}}\multiput(6,19.35)(2,0){15}{\line(0,1){1.3}}\put(20,20){\circle*{1}}\put(22,22){\sf O(0, 0)}\put(20,28){\circle*{1.1}}\put(20,28){\circle{2}}\put(21,28){\sf A(0, 4)}\put(20,38){\sf Y}\put(21,2){\sf Y'}\put(2,21){\sf X'}\put(37,21){\sf X}\end{picture}

\sf\pink{Answer\::}

The point (0,4) is located on the y axis in between 1st quadrant on cartisian plane.

\rule{130}1

\huge \sf\gray{Extra\:Shots\::}

The cartisian plane is defined by two perpendicular number lines, x axis (horizontal line), and y axis (vertical line).

  • The cartisian plane is divided into 4 quadrants.
  • The first quadrant both x and y ordinate both are positive.
  • The second quadrant x ordinate is negative and y ordinate is positive.
  • The third quadrant both x and y ordinate are negative.
  • In fourth quadrant x ordinate is positive and y ordinate is negative.

\rule{170}2

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