Answer:Dos triángulos son congruentes si tienen iguales dos de sus lados respectivos y el ángulo comprendido entre ellos y el ángulo opuesto mayor medida que ellos. 4° Dos triángulos son congruentes si tienen dos lados correspondientes y el ángulo opuesto mayor de estos lados congruentes.
Step-by-step explanation:
Answer:
They are not equal to each other
Step-by-step explanation:
3^2 + 2^2 = C^2
9+4=C^2
13=c^2
3.6= CD
2^2 +2^2 =c^2
4+4 =c^2
8=c^2
2.8= EF
Answer:
b. divide them into groups based on similarities
Step-by-step explanation:
Blocking is a method in statistics used to reduce the effect of nuisance variables in an experiment. Nuisance variables are those factors that could result in variations during the experiment. During blocking, subjects with similar features are grouped in the same block, and treatment is then administered to each of these subjects. In order to form blocks, blocking factors are used.
Blocking factors can affect the results of an experiment but they are of no importance to the experimenter. An example of a blocking factor is age. So, for Isamu who seeks to use blocking to deal with an extraneous factor in his experiment, blocking would enable him to divide his subjects into groups based on similarities.
To solve this equation you need to first start by writing out the f(x)-g(X).
The equation should be 2x^2-4x-5+2x.
You then want to simplify the equation, I got 2x^2-2x-5.
You then want to plug in the x=5 for all the x's in the equation.
2(5)^2-2(5)-5 would be the equation.
The answer you get should be 35.
Given:
The equation for the area of the first option is:
Where x is the side length of the current square park.
To find:
The side length of the current square park.
Solution:
We have,
It can be written as:
Splitting the middle term, we get
We know that the side length of a park cannot be negative. So, the only possible value of x is 320.
Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.
