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Ivenika [448]
4 years ago
12

Carmen earns a base pay of $15 plus $0.17 for every pamphlet that she delivers.how much will she earn if she delivers 300 pamphl

ets in one week?
Mathematics
1 answer:
Anna71 [15]4 years ago
3 0

Answer:

$66

Step-by-step explanation:

Y=0.17x+15

Y=0.17(300)+15

Y=66

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It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2
Sonbull [250]

Answer:

15 g.

Step-by-step explanation:

The following data were obtained from the question:

Heat required (Q) = 350 J

Initial temperature (T1) = 10.0 °C

Final temperature (T2) = 30.0 °C

Specific heat capacity (C) = 1.2 J/g°C

Mass (M) =..?

Next, we shall determine the change in temperature.

This is illustrated below:

Initial temperature (T1) = 10.0 °C

Final temperature (T2) = 30.0 °C

Change in temperature (ΔT) =..?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 30 – 10

Change in temperature (ΔT) = 20 °C

Finally, we shall determine the mass of the substance as follow:

Heat required (Q) = 350 J

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Change in temperature (ΔT) = 20 °C

Mass (M) =.?

Q = MCΔT

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3 years ago
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Answer:

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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

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120 = k/1^2

Multiply both sides by 1^2 to find k

k = 120

Substitute new values in:

r = 120/10^2

Solve:

r = 1.2

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

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