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3 years ago

PLEASE I REALLY NEED HELP

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Answer:

who think

Step-by-step explanation:

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Is there a solution y=3x+1 y=3x+5

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Answer:y = 3x + 5 is a linear equation in two variables and it has infinite possible solutions.

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A two digit number with two different digits has a special property when th sum of its digits is added to the product of its dig

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What two simpler problem can you use to find 9×38?

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3 years ago

Which of the following equations have complex roots?

mestny [16]

Answer:

Step-by-step explanation:

Complex roots of quadratic functions occur when the discriminant is negative.

Discriminant

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$

Evaluate the discriminant of each of the given equations.

$\textsf{A.} \quad 3x^2+2=0$

$\implies a=3, \quad b=0, \quad c=2$

$\implies b^2-4ac=0^2-4(3)(2)=-24$

As -24 < 0 the equation will have complex roots.

$\textsf{B.} \quad 2x^2+1=7x$

$\implies 2x^2-7x+1=0$

$\implies a=2, \quad b=-7, \quad c=1$

$\implies b^2-4ac= (-7)^2-4(2)(1)=41$

As 41 > 0 the equation does not have complex roots.

$\textsf{C.} \quad 3x^2-1=6x$

$\implies 3x^2-6x-1=0$

$\implies a=3, \quad b=-6, \quad c=-1$

$\implies b^2-4ac=(-6)^2-4(3)(-1)=48$

As 48 > 0 the equation does not have complex roots.

$\textsf{D.} \quad 2x^2-1=5x$

$\implies 2x^2-5x-1=0$

$\implies a=2, \quad b=-5, \quad c=-1$

$\implies b^2-4ac=(-5)^2-4(2)(-1)=33$

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0

2 years ago

The answer for your question is a 1;3 because 16/48=1/3 or 1:3.

tiny-mole [99]

1:3 = 16/48 and 1/3.

Have a nice day! :D

4 0

3 years ago