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2 years ago

Banks are private and credit unions are nonprofit organizations owned by the people.

Mathematics

1 answer:

Bezzdna [24]2 years ago

4 0

Answer:

The answer is False.

Hope this helps you.

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One of the ancient stone pyramids in Egypt has a square base that measures 140 m on each side. The height is 96 m. What is the v

miv72 [106K]

Volume of a pyramid = $\frac{1}{3}*base*height$

Given base is = 140 m

Given height is = 96 m

Volume = $\frac{1}{3}\times140\times96=4480$

Hence, volume of pyramid is 4480 m³

4 0

2 years ago

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$

B) Here X is Bin (8, 0.1)

$P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488$

C) Here X is Bin (20,5)

$P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319$

3 0

2 years ago

I need correct answer for this

dybincka [34]

Answer:

should be 82%

Step-by-step explanation:

Hope this helps!

6 0

2 years ago

Read 2 more answers

Please help ? Thanks

rjkz [21]

Try answer C or B because either one could be the right answer

8 0

2 years ago

Read 2 more answers

Particle 1 of charge q1 �� 5.00q and particle 2 of charge q2 �� 2.00q are fixed to an x axis. (a) as a multiple of distance

Naya [18.7K]

Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get

k q1 / d^2 = - k q2 / (d-1)^2

Rearranging to calculate for d:

(d-1)^2/d^2 = -q2/q1 = 0.4 
 d^2-2d+1 = 0.4d^2 
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207

We pick the value that is > q2 hence,

d = 2.72075922005613*L

d = 2.72*L

3 0

2 years ago