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2 years ago

June has $1.95 in dimes and nickels. She has a total of 28 coins. how many of each type of coin does she have?

Mathematics

2 answers:

Dovator [93]2 years ago

7 0

Answer:

11 dimes, 17 nickels

Step-by-step explanation:

d + n = 28, put one variable by itself on a side, d = 28 - n

.10d + .05n = 1.95

Sub the first equation into the second

.10(28 - n) + .05n = 1.95

2.8 - .10n + .05n = 1.95

2.8 - .05n = 1.95

-.05n = -0.85

n = 17 nickels

d + 17 = 28

d = 11 11 dimes

GrogVix [38]2 years ago

3 0

Answer:

17 nickles 11 dimes

Step-by-step explanation:

don't feel like it You know the answer you don't need this

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2 years ago

Help me please thank you!

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Read 2 more answers

If <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2" id="TexFormula1" title="f(x)=x^2-2" alt="f(x)=x^2-2" align="absmiddle"

jek_recluse [69]

Answer:

$\boxed{f(6) = 34}$

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

$g(2) = 3(2)$

$g(2) = 6$

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$