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4 years ago

What is the inverse of the function f(x) = 4x + 8?

Mathematics

1 answer:

Amanda [17]4 years ago

6 0

<h3>Answer: h(x) = (1/4)x - 2 which is choice A</h3>

How to get this answer:

Replace f(x) with y. Then swap x and y. Lastly, solve for y to get the inverse.

f(x) = 4x+8

y = 4x+8

x = 4y+8

x-8 = 4y

4y = x-8

y = (x-8)/4

y = x/4 - 8/4

y = (1/4)x - 2

h(x) = (1/4)x - 2

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What is the answer to 2y-4x=-18 ?

Ganezh [65]

Answer: y=-2x-9

Step-by-step explanation:

Add 4x to both sides because the slope (-2x) needs to be on the same side as the y-intercept (-9). Then divide everything by 2 to get your answer because you want to get y by itself, since there is two of them. 2y-4x=-18 becomes y=-2x-9.

7 0

3 years ago

Can anyone help me solve this? Please and thank you!

AveGali [126]

It's the sum of a geometric sequence.

Let's rewrite it a bit:

$\displaystyle\\\sum_{n=1}^{10}8\left(\dfrac{1}{4}\right)^{n-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot \left(\dfrac{1}{4}\right)^{-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot 4=32\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$

And now let's calculate this sum $\displaystyle \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$ :

$S_n=\dfrac{a(1-r^n)}{1-r}\\\\a=\dfrac{1}{4}\\n=10\\r=\dfrac{1}{4}\\\\S_{10}=\dfrac{\dfrac{1}{4}\cdot\left(1-\left(\dfrac{1}{4}\right)^{10}\right)}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{4}\cdot\left(1-\dfrac{1}{1048576}\right)}{\dfrac{3}{4}}=\dfrac{\dfrac{1048575}{1048576}}{3}=\dfrac{1048575}{3145728}=\\=\dfrac{349525}{1048576}$

Now let's calculate the initial sum:

$\displaystyle 32\cdot \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n=32\cdot \dfrac{349525}{1048576}=\dfrac{349525}{32768}\approx10.67$

8 0

2 years ago

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

Tom [10]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

$A=7330.025820498\approx 7330.03$

When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

$A=7418.9916619456\approx 7419.00$

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

3 0

3 years ago

10) 9 1/4 gt to<br>C (Show your work)<br>Your answer<br>This is a required question

vredina [299]

37 (Multiply by 4,111)

4 0

4 years ago

Which function is continous across its domain? Pls help

vichka [17]

Answer:

Step-by-step explanation:

A function f is continuous on its domain D if f is continuous at every point c∈D. Example 1. The function f(x)=ex (with domain R) is continuous on its domain.

4 0

3 years ago