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Sindrei [870]
3 years ago
9

Suppose you roll a special 25 sided die. What is the probability that the number rolled is 1 or 2?

Mathematics
2 answers:
choli [55]3 years ago
7 0
2/25ths or 0.08 percent chance
yuradex [85]3 years ago
3 0
The answer is 21 I think not
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At the toll booth, the chance that a driver has exact change is 1/4, independent of vehicle. Find the probability that no vehicl
MAXImum [283]

Answer:

g

Step-by-step explanation:

 b

4 0
3 years ago
Estimated a 3 out of every 25 men are left handed<br> what percent of men are left ahnded
Yuki888 [10]

Answer:

12

Step-by-step explanation:

Percent means out of 100

We have 3/25

Multiply the top and bottom by 4

12/100

The percent is 12

7 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
Can someone pls help me?
Setler [38]
I believe the answer is AD=7.0
4 0
3 years ago
I need help with: 100 textbooks increased by 99%. Is it 199??
yarga [219]
Hey there! :D

99%=.99

100*.99= 99 

100+99= 199

So, you would be correct. 99% of 100= 99 Nice work!

I hope this helps!
~kaikers
6 0
3 years ago
Read 2 more answers
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