All categories

3 years ago

What is the solution to the following equation? -32-8x=-7x+8(8x-4)

Mathematics

2 answers:

Lilit [14]3 years ago

8 0

the answer to your question is x=0

makkiz [27]3 years ago

5 0

X=0

−32−8x=−7x+8(8x−4)

−8x−32=−7x+8(8x−4)

−8x−32=−7x+64x−32

−8x−32=57−32

−8−32+32=57−32+32

−8=57

You might be interested in

What type of line is perpendicular to a linear equation that is not a function

enyata [817]

Answer:

Determine whether lines are parallel or perpendicular given their equations; Find equations of . We can begin by using point-slope form of an equation for a line. No. For two perpendicular linear functions, the product of their slopes is –1.

Step-by-step explanation:

6 0

3 years ago

Which expression is equivalent to...

torisob [31]

Answer:

$x^{\frac{2}{7} } y^{-\frac{3}{5} } \\$ i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

$\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\$

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

$y^{-\frac{3}{5} } \\$

So the answer is: $x^{\frac{2}{7} } y^{-\frac{3}{5} } \\$

7 0

3 years ago

Find a vector parametric equation r⃗(t) for the line through the points P=(1,0,−2) and Q=(1,5,1) for each of the given condition

const2013 [10]

So the question ask to find and calculate the vector parametric equation r(t) for the line through the points P=(1,0,-2) and Q(1,5,1) for each given condition. And the possible vector parametric equation is <1,2,-2>+t/4<1,5,3>. I hope you are satisfied with my answer and feel free to ask for more

7 0

3 years ago

1/16^3x=64^2(x+8)<br> Solve for x.

SSSSS [86.1K]

Answer:

x = -4

Step-by-step explanation:

16 = 4*4 = 4²

64 = 4 * 4* 4 = 4³

$(\dfrac{1}{16})^{3x}=64^{2*(x+8)}\\\\\\(16^{-1})^{3x}=64^{2x + 16}\\\\\\16^{-3x}=64^{2x +16}\\\\(4^{2})^{-3x}=(4^{3})^{2x+16}\\\\4^{-6x}=4^{6x +48}$

As bases are same, compare exponents

6x + 48 = -6x

Subtract 48 from both sides

6x = -6x - 48

Add '6x' to both sides

6x + 6x = -48

12x = -48

Divide both sides by 12

x = -48/12

x = -4

3 0

2 years ago

Which coordinate point is a solution to the linear equation? (The graph counts by 1s)

Harman [31]

Answer:

the point through which it passes i.e (1,5)

5 0

2 years ago

Read 2 more answers