Answer:
Option A
Step-by-step explanation:
Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF
Area of ΔABH = 
= 
= 9 in²
Area of the trapezoid = 
= 
= 25 in²
Area of ΔDEF = 
= 24 in²
Therefore, area of the given figure = 9 + 25 + 24
= 58 in²
Option A will be the correct option.
We are told to use simple interest rate. Formula for this is:
Where:
A= total accumulated amount (principal + interest)
P= principal
r= yearly percentage rate
t= number of years
We need to save $19500 for the first year at a college. This is the amount we will have at the account after five years. In our case this is A.
Principal is the amount we need to put into savings to get the total amount needed. In our case this is P.
Yearly percentage rate is the percentage by which our savings increase at the end of a year. In our case this is r.
t is number of years that we are holding our money on the bank account.
To solve this problem we will assume that we are putting same amount each month on the bank account.
We are given:
A=$19500
P=?
r=1.5%
t=5 years
First step is to transform r into decimal number:
Now we get back to our formula and we solve it for P:
We insert numbers and we get our principal:
We need to put $18139.53 into savings to get required amount after 5 years or 5*12=60months. Assuming that we put same amount each month into savings we need to put
This is our solution for this problem. This is closest to the amount we would need to put in real life. In real life we would earn interest onto interest and our monthly amount would be smaller.
Hello!
We can solve this algebraically
2x + 5 = 3 + 2(x+1)
Distribute the 2
2x + 5 = 3 + 2x + 2
combine like terms
2x + 5 = 2x + 5
Since both sides of the equation is the same all values of x make the equation true
The answer is A
Hope this helps!
Answer:
<h3>Ur answer refer to above attachment </h3><h3>Hope this help u XD ✌️</h3>
<h3>Not copied answer </h3>
<h2>ItzSneha~</h2>
The answer would be 12/54 (twelve fifty fourths) but if you simplify it you would get 2/9 (two ninths).
