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makvit [3.9K]
3 years ago
9

In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t

he cross section be x and formed a right triangle with hypotenuse r, as shown below.
The cross-sectional area of the shaded circle is πx2. Using the Pythagorean theorem for the right triangle, we get x2 + b2 = r2. Now solve for x2 and substitute it into the area expression.

What is the result?

π(r2 – b2)
π(r2 + b2)
π(b2 – r2)
2π(b2 + r2)
Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

it's A

Step-by-step explanation:

Just took the assignment on EDG

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