In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t

Question

3 years ago

9

In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t

he cross section be x and formed a right triangle with hypotenuse r, as shown below.
The cross-sectional area of the shaded circle is πx2. Using the Pythagorean theorem for the right triangle, we get x2 + b2 = r2. Now solve for x2 and substitute it into the area expression.

What is the result?

π(r2 – b2)
π(r2 + b2)
π(b2 – r2)
2π(b2 + r2)

Mathematics

1 answer:

ra1l [238] · Answer 1 · 2022-07-30T11:11:23+03:00

ra1l [238]3 years ago

7 0

Answer:

it's A

Step-by-step explanation:

Just took the assignment on EDG