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Ivan
3 years ago
14

2 bromocyclopentanamine

Chemistry
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

The structure is given in attached file.

Explanation:

2-bromocyclopentamine (Figure attached) is a synthetic compound which is synthesized by substitution reaction of cyclopentamine and hydrobromide. Its molecular formula and molecular mass are C5H10NBr and 164.05 g/mol respectively.  It is a very reactive compound so it doesn’t available in pure form, it is present in market as a mixture of 2-bromocyclopentamine and Hydrobromide.

Properties :

Its boiling point is 115 °C.

Its melting point is -75 °C .

It is highly flammable .

It is highly toxic .

It is irritant .

It is corrosive in nature.

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Ghella [55]

Answer:

Up to 80 - 120 days.

Explanation:

The flower will probably stay six to twelve days or so.

I'm not sure what's your hypothesis going to be, but I'll give you an example.

" <em>If</em>  I __________, <em>then</em> the sunflower will grow up to 80 to 120 days."

In the blank space, you can write what you're going to do to your sunflower during the experiment.

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5 0
3 years ago
Calculate the wavelength of an electron (m = 9.11 x 10-28 g) moving at 3.66 x 100 m/s. A) 1.81 x 10-10 m B) 2.76 x 10-9 m C) 5.0
inna [77]

Answer:

option e = 1.99 × 10⁻⁶ m

Explanation:

Given data:

Mass of electron = 9.11 × 10⁻²⁸ g   or 9.11 × 10⁻³¹ Kg

Velocity = 3.66 × 100 m/s

Wavelength = ?

Solution:

Formula:

λ  = h / m. v

λ  = wavelength

h = planck's constant

m = mass

v = velocity

Now we will put the values in equation

λ  = h / m. v

λ  =  6.63 × 10⁻³⁴ Kg. m²/s  / 3.66 × 100 m/s . 9.11 × 10⁻³¹ Kg

λ  =  6.63 × 10⁻³⁴ Kg. m²/s / 3334.26  × 10⁻³¹ Kg .m/s

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7 0
3 years ago
Read 2 more answers
When 4.21 grams of potassium hydroxide are added to 250 mL of water in a coffee cup calorimeter, the temperature rises by 4.14°C
Schach [20]

Answer:

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

Explanation:

<u>Step 1:</u> Data given

Mass of potassium hydroxide = 4.21 grams

Volume of water = 250 mL

Temperature rise = 4.14 °C

Density = 1g/mL

Specific heat = 4.184 J/g°C

<u>Step 2:</u> Calculate the heat absorbed by water

q = m*c*ΔT

⇒ with m = the mass of water = 250 grams

⇒ with c= the specific heat of the solution = 4.184 J/g°C

⇒ with ΔT = 4.14 °C

q = 250 * 4.184*4.14 = 4330.4 J

<u>Step 3:</u> Calculate moles of KOH

Moles KOH = Mass KOH / Molar mass KOH

Moles KOH = 4.21 grams / 56.106 g/mol

Moles KOH = 0.075 moles

<u>Step 4:</u> Calculate molar heat of solution

4330.4 J / 0.075 moles = 57738.7 j/mol = 57.7 kJ /mol

(Note that the enthalpy change for the reaction is negative because the reaction is exothermic)

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

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4 years ago
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7 0
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